Area of Path and Verandah
Area of Path and Verandah
Area of Path & Verandah:
It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m
32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m
22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
A rectangular lawn is 15 m by 40 m .It has two roads each 4 m wide running in the middle of it, one parallel to the length and the other parallel to the breadth . Find the area of the roads. | |||
| Right Option : A | |||
| View Explanation | |||
A plot is 100 m long and 60 m broad.A path 5 m wide runs breadth wise across the ground in the middle.Find the area of path.
| |||
| Right Option : B | |||
| View Explanation | |||
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A square lawn is surrounded by a path 3 m wide. If the area of the path is 360 sq m. Find the area of the lawn. | |||
| Right Option : A | |||
| View Explanation | |||
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